(t^2-2t)^2+6(t^2-2t)=7

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Solution for (t^2-2t)^2+6(t^2-2t)=7 equation: 



(t^2-2t)^2+6(t^2-2t)=7

We move all terms to the left:

(t^2-2t)^2+6(t^2-2t)-(7)=0

We multiply parentheses

6t^2+(t^2-2t)^2-12t-7=0

We add all the numbers together, and all the variables

6t^2-12t+(t^2-2t)^2-7=0

We move all terms containing t to the left, all other terms to the right

6t^2-12t+(t^2-2t)^2=7

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